How do you find the definite integral of #sqrt(y+1)dy# from #[0,3]#?

Answer 1

I found: #14/3#

We can try this:

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

To find the definite integral of √(y + 1) dy from 0 to 3, you first need to find the antiderivative of √(y + 1) with respect to y, and then evaluate it at the upper limit (3) and subtract the value at the lower limit (0). The antiderivative of √(y + 1) with respect to y is (2/3)(y + 1)^(3/2). Therefore, the definite integral from 0 to 3 is [(2/3)(3 + 1)^(3/2)] - [(2/3)*(0 + 1)^(3/2)]. Simplify these expressions to get the final answer.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7