# How do you find the critical numbers of #f(x)=x^2-6x#?

Critical point exist at

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To find the critical numbers of ( f(x) = x^2 - 6x ), we first find its derivative, ( f'(x) ), then set it equal to zero and solve for ( x ).

So, the derivative of ( f(x) ) is ( f'(x) = 2x - 6 ).

Setting ( f'(x) ) equal to zero, we get:

( 2x - 6 = 0 )

Solving for ( x ), we have:

( 2x = 6 ) ( x = 3 )

Therefore, ( x = 3 ) is the critical number of ( f(x) = x^2 - 6x ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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