How do you find the critical numbers of #9x^3  25x^2#?
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To find the critical numbers of (9x^3  25x^2), first, you need to find the derivative of the function and then solve for (x) when the derivative equals zero.

Find the derivative of the function: [f'(x) = 27x^2  50x]

Set the derivative equal to zero and solve for (x): [27x^2  50x = 0] Factor out (x): [x(27x  50) = 0]

Set each factor equal to zero and solve for (x): [x = 0] [27x  50 = 0] Solving for (x): [27x = 50] [x = \frac{50}{27}]
So, the critical numbers of (9x^3  25x^2) are (x = 0) and (x = \frac{50}{27}).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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