# How do you find the c that makes the trinomial #x^2+22x+c# a perfect square?

Which gives

This is a process called 'Completing the Square' and does exactly what the name implies...

To complete means to add what is missing

You are trying to create a perfect square, in this case the square of a binomial.

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To find the constant (c) that makes the trinomial (x^2 + 22x + c) a perfect square, follow these steps:

- Identify the coefficient of the linear term, which is (22).
- Divide the coefficient of the linear term by (2), then square the result. This gives us (\left(\frac{22}{2}\right)^2 = 121).
- The constant (c) that makes the trinomial a perfect square is equal to the squared result from step 2, so (c = 121).

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To find the constant ( c ) that makes the trinomial ( x^2 + 22x + c ) a perfect square, you can use the formula:

[ c = \left(\frac{b}{2}\right)^2 ]

In this case, ( b = 22 ). So:

[ c = \left(\frac{22}{2}\right)^2 = 11^2 = 121 ]

Therefore, the constant ( c ) that makes the trinomial a perfect square is ( c = 121 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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