How do you find the axis of symmetry of the quadratic equation #y = 2(x + 7)^2 – 4#?
x = -7
Y is in the vertex form, and the axis of symmetry and the vertex's x-coordinate are both x = -7.
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To find the axis of symmetry of the quadratic equation y = 2(x + 7)^2 - 4, you use the formula for the axis of symmetry of a parabola, which is x = -b/2a. In this equation, a = 2 and b = 0. Therefore, the axis of symmetry is x = -0 / (2 * 2) = 0. So, the axis of symmetry is x = -7.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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