How do you find the axis of symmetry and vertex point of the function: #y= -x^2-4x+5#?
The axis of symmetry is
The vertex is
graph{y=-x^2-4x+5 [-14.95, 13.52, -3.76, 10.48]}
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To find the axis of symmetry of a quadratic function in the form y = ax^2 + bx + c, you use the formula x = -b / (2a). For the given function y = -x^2 - 4x + 5, a = -1 and b = -4. Substituting these values into the formula, we get x = -(-4) / (2 * -1) = 4 / -2 = -2. So, the axis of symmetry is x = -2. To find the vertex point, substitute the value of x = -2 into the original function: y = -(-2)^2 - 4(-2) + 5 = -4 + 8 + 5 = 9. So, the vertex point is (-2, 9).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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