# How do you find the axis of symmetry and vertex point of the function: #y = x^2 − 1#?

Rewrite in explicit vertex form and recognize it as a parabola in standard position.

Vertex:

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To find the axis of symmetry of a quadratic function in the form ( y = ax^2 + bx + c ), you can use the formula ( x = -\frac{b}{2a} ). For the given function ( y = x^2 - 1 ), ( a = 1 ) and ( b = 0 ). Plugging these values into the formula, we get ( x = -\frac{0}{2(1)} = 0 ). So, the axis of symmetry is ( x = 0 ).

To find the vertex point, substitute the value of ( x ) found for the axis of symmetry into the original function. So, when ( x = 0 ), ( y = (0)^2 - 1 = -1 ). Therefore, the vertex point is ( (0, -1) ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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