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How do you find the axis of symmetry and vertex point of the function: #y=2x^2+6x+4#?

Answer 1

Find vertex of #y = 2x^2 + 6x + 4#

x-coordinate of axis of symmetry and of vertex: #x = (-b/2a) = -6/4 = -3/2# y-coordinate of vertex: #y = f(-3/2) = 2(9/4) + 6(-3/2) + 4 = 18/4 - 18/2 + 4 = -2/4 = -1/2# graph{2x^2 + 6x + 4 [-5, 5, -2.5, 2.5]}

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Answer 2

Abigail Allen

To find the axis of symmetry of the function (y = 2x^2 + 6x + 4), you use the formula (x = -\frac{b}{2a}), where (a = 2) and (b = 6). To find the vertex point, substitute the value of (x) found into the original equation to get the corresponding (y)-coordinate.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.