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How do you find the axis of symmetry and vertex point of the function: #y = 2x^2 – 12x + 22#?

Answer 1

Vertex of #y = 2x^2 - 12x + 22#

Ans: Vertex (3, 4)

x-coordinate of axis of symmetry and vertex: #x = (-b/2a) = 12/4 = 3# y-coordinate of vertex: y = f(3) = 18 - 36 + 22 = 4 graph{2x^2 - 12x + 22 [-20, 20, -10, 10]}

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Answer 2

Genesis Allen

To find the axis of symmetry, use the formula x = -b / (2a), where a = 2 and b = -12. Then substitute the value of x into the equation to find the corresponding y-coordinate for the vertex point.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.