How do you find the axis of symmetry and the vertex for the line #y = x^2 - 6x +11#?
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To find the axis of symmetry for the quadratic equation y = x^2 - 6x + 11, use the formula: x = -b / (2a). In this equation, 'a' is the coefficient of x^2 (which is 1), and 'b' is the coefficient of x (which is -6). So, x = -(-6) / (2 * 1) = 3. To find the vertex, substitute the value of x = 3 into the equation y = x^2 - 6x + 11. So, y = (3)^2 - 6(3) + 11 = 2. Therefore, the axis of symmetry is x = 3, and the vertex is (3, 2).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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