# How do you find the axis of symmetry, and the maximum or minimum value of the function #f(x)=3(x+2)(x-2)#?

Multiply out the brackets

From above the graph is symmetrical about the y-axis. Consequently y-vertex must be at the point where the graph crosses the y axis, which is:

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To find the axis of symmetry of the function ( f(x) = 3(x+2)(x-2) ), use the formula: ( x = \frac{-b}{2a} ). In this function, ( a = 3 ) and ( b = 0 ), so the axis of symmetry is ( x = \frac{0}{2 \cdot 3} = 0 ).

To find the maximum or minimum value of the function, you can use the vertex form of a quadratic function: ( f(x) = a(x-h)^2 + k ), where ( (h, k) ) is the vertex. In this case, ( h = 0 ), so the maximum or minimum value occurs at ( x = 0 ). Plugging ( x = 0 ) into the function gives ( f(0) = 3(0+2)(0-2) = -12 ).

Therefore, the axis of symmetry is ( x = 0 ), and the minimum value of the function is ( -12 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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