# How do you find the average value of #f(x)=4x^(1/2)# as x varies between #[0,3]#?

The average value of

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To find the average value of (f(x) = 4x^{1/2}) as (x) varies between ([0,3]), you can use the formula for the average value of a function on a closed interval. It is given by (\frac{1}{b-a} \int_a^b f(x) , dx), where (a) and (b) are the limits of integration. Substitute (a = 0) and (b = 3) into this formula and calculate the definite integral of (f(x)) over the interval ([0,3]). Then divide the result by (b-a), which is (3 - 0 = 3). This will give you the average value of (f(x)) on the interval ([0,3]).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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