How do you find the average rate of change of the function #f(x)=4 ·x^2 + 2 ·x−4# over the interval [3, 3.17]?
The average rate of change of a function
So, here's where the math comes in:
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To find the average rate of change of the function ( f(x) = 4x^2 + 2x - 4 ) over the interval ([3, 3.17]), you calculate the difference in the function values at the endpoints of the interval and divide by the difference in the x-values.
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Evaluate the function at the endpoints of the interval:
- ( f(3) = 4(3)^2 + 2(3) - 4 = 36 + 6 - 4 = 38 )
- ( f(3.17) = 4(3.17)^2 + 2(3.17) - 4 = 40.0568 + 6.34 - 4 = 42.3968 )
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Calculate the difference in function values: ( 42.3968 - 38 = 4.3968 ).
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Calculate the difference in x-values: ( 3.17 - 3 = 0.17 ).
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Divide the difference in function values by the difference in x-values: ( \frac{4.3968}{0.17} \approx 25.861 ).
So, the average rate of change of the function over the interval ([3, 3.17]) is approximately (25.861).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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