How do you find the asymptotes for #sin^2x#?

Answer 1

vertical asymptotes: none
horizontal asymptotes: none
slant/oblique asymptotes: none

The #sin^{2}x# function is continuous across the entire domain of all real numbers, so there are no vertical asymptotes.

The #sin^{2}x# function oscillates back and forth between all values in it's range of #[0, 1]#, so it doesn't have any horizontal or slant/oblique asymptotes either.

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Answer 2

Elias Ackerman

The function ( \sin^2(x) ) does not have asymptotes. It represents the square of the sine function, which oscillates between -1 and 1 for all real values of ( x ). As such, it does not exhibit asymptotic behavior.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.