# How do you find the area under the graph of #f(x)=x^2# on the interval #[-3,3]# ?

Watch this problem solved here.

By signing up, you agree to our Terms of Service and Privacy Policy

To find the area under the graph of ( f(x) = x^2 ) on the interval ([-3, 3]), you can use definite integration. You integrate ( f(x) ) with respect to ( x ) from (-3) to (3), which means finding the integral of ( x^2 ) from (-3) to (3). This can be represented mathematically as:

[ \int_{-3}^{3} x^2 , dx ]

Evaluating this integral will give you the area under the graph of ( f(x) = x^2 ) on the interval ([-3, 3]).

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- The region under the curve #y=sqrt(1+x^2)# bounded by #0<=x<=1# is rotated about a) the x axis and b) the y axis. How do you sketch the region and find the volumes of the two solids of revolution?
- The region under the curves #y=sqrt(e^x+1), 0<=x<=3# is rotated about the x axis. How do you sketch the region and find the volumes of the two solids of revolution?
- The base of a solid region in the first quadrant is bounded by the x-axis,y-axis, the graph of #y=x^2+1#, and the vertical line x=2. If the cross sections perpendicular to the x-axis are squares, what is the volume of the solid?
- How do you sketch the region enclosed by #y=1+sqrtx, Y=(3+x)/3# and find the area?
- How do you find the area of the region bounded by the curves #y=sin(x)#, #y=e^x#, #x=0#, and #x=pi/2# ?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7