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How do you find the area of #triangle ABC# given #B=92^circ, a=14.5, c=9#?

Answer 1

Samantha Abate

#"Area" = 65.21#

We can use the formula #"Area" = 1/2acsinB# to find the area of the triangle.

Let's input the given values to solve for the area: #"Area" = 1/2(14.5)(9)sin92^@#

And after you type this into your calculator, you should get #"Area" ~~ 65.21# (rounded to nearest hundredth's place)

I hope this is useful.

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Answer 2

Nolan Alexander

To find the area of triangle ABC given ( B = 92^\circ ), ( a = 14.5 ), and ( c = 9 ), you can use the formula for the area of a triangle:

[ \text{Area} = \frac{1}{2} \times a \times c \times \sin(B) ]

Substitute the given values into the formula:

[ \text{Area} = \frac{1}{2} \times 14.5 \times 9 \times \sin(92^\circ) ]

Calculate the value of ( \sin(92^\circ) ), which is approximately ( 0.9994 ), then compute the area using this value:

[ \text{Area} = \frac{1}{2} \times 14.5 \times 9 \times 0.9994 ]

[ \text{Area} \approx 65.91 ]

Therefore, the area of triangle ABC is approximately ( 65.91 ) square units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.