# How do you find the area of #triangle ABC# given #B=92^circ, a=14.5, c=9#?

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To find the area of triangle ABC given ( B = 92^\circ ), ( a = 14.5 ), and ( c = 9 ), you can use the formula for the area of a triangle:

[ \text{Area} = \frac{1}{2} \times a \times c \times \sin(B) ]

Substitute the given values into the formula:

[ \text{Area} = \frac{1}{2} \times 14.5 \times 9 \times \sin(92^\circ) ]

Calculate the value of ( \sin(92^\circ) ), which is approximately ( 0.9994 ), then compute the area using this value:

[ \text{Area} = \frac{1}{2} \times 14.5 \times 9 \times 0.9994 ]

[ \text{Area} \approx 65.91 ]

Therefore, the area of triangle ABC is approximately ( 65.91 ) square units.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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