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How do you find the area of the rectangle with vertices A(-3,0), B(-2,-1), C(1,2), D(0,3)?

Answer 1

Nathan Axel

#6# sq. units

#"Area"_square = "Length" xx "Width"#

Using #|AB|# as the "Width" and #|AD|# as the "Length"

#|AB| = sqrt((-3-(-2))^2+(0-(-1))^2)=sqrt(2)# #|AD|=sqrt((-3-0)^2+(0-3)^2)=3sqrt(2)#

#"Area"_square = 3sqrt(2)xxsqrt(2)=6#

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Answer 2

Julia Adams

Area#=6# square units

Area #=(1/2)*(x_a*y_b+x_b*y_c+x_c*y_d+x_d*y_a-x_b*y_a-x_c*y_b-x_d*y_c-x_a*y_d)#

Area #=(1/2)*(-3(-1)+(-2)(2)+(1)(3)+0(0)-[0(-2)+(-1)(1)+2(0)+(3(-3])#

Area #=(1/2)*(6-4-(-10))#

Area#=6#

Have a nice day !! from the Philippines...

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Answer 3

Jameson Allen

To find the area of the rectangle with vertices A(-3,0), B(-2,-1), C(1,2), D(0,3), you can use the distance formula to find the lengths of the sides AB, BC, CD, and DA. Then, use the formula for the area of a rectangle, which is length times width, where the lengths are the lengths of opposite sides of the rectangle.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.