How do you find the area of the rectangle given the side of it is 3-√10 the bottom is 4√10?
120 square units
The area of a rectangle is A = lb , where l , is the length and b , the breadth.
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To find the area of a rectangle with sides ( 3 - \sqrt{10} ) and ( 4\sqrt{10} ), you multiply the length by the width:
[ \text{Area} = \text{length} \times \text{width} = (3 - \sqrt{10}) \times 4\sqrt{10} ]
[ \text{Area} = 12\sqrt{10} - 4\sqrt{10}\sqrt{10} = 12\sqrt{10} - 4 \times 10 = 12\sqrt{10} - 40 ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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