# How do you find the area of the parallelogram with vertices (4,5), (9, 9), (13, 10), and (18, 14)?

Calculate the areas of the four trapezoids formed by the line segments, the X-axis, and the line segments joining the given vertices to the X-axis.

Subtract the lower two trapezoid areas from the upper two.

General form of Trapezoid Area =

Area of parallelogram

(always assuming my basic arithmetic is correct).

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To find the area of the parallelogram with vertices (4,5), (9, 9), (13, 10), and (18, 14), you can use the Shoelace Formula. First, write down the coordinates in order as (x1, y1), (x2, y2), (x3, y3), (x4, y4). Then, apply the formula:

Area = 1/2 * |(x1*y2 + x2*y3 + x3*y4 + x4*y1) - (y1*x2 + y2*x3 + y3*x4 + y4*x1)|

Substitute the coordinates into the formula:

Area = 1/2 * |(4*9 + 9*10 + 13*14 + 18*5) - (5*9 + 9*13 + 10*18 + 14*4)|

Calculate the values:

Area = 1/2 * |(36 + 90 + 182 + 90) - (45 + 117 + 180 + 56)|

Area = 1/2 * |(398) - (398)|

Area = 1/2 * |0|

Area = 0 square units

Therefore, the area of the parallelogram is 0 square units.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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