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How do you find the area of the largest isosceles triangle having a perimeter of 18 meters?

Answer 1

Use Lagrange multiplier
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Using the wikipwdia notation: f(x,y)-function that you want to maximize (area of the triangle) g(x,y)- function that is your "bond" (perimeter) written in equation form g(x,y)=0 #L(x,y, lambda) =f(x,y)-lambda*g(x,y) # Maximaze #L(x,y,lambda)#:

express #x, y or lambda# end put it in the 3. equation

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Answer 2

Christopher Allers

To find the area of the largest isosceles triangle with a perimeter of 18 meters, divide the perimeter by 2 to find the length of each equal side. Then, use the formula for the area of a triangle: Area = (base * height) / 2. In an isosceles triangle, the base is one of the equal sides, and the height can be found using the Pythagorean theorem. Once you have the base and height, plug them into the formula to calculate the area.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.