How do you find the area of a trapezoid with vertices (-7,1) (-4,4) (-4,-6) and (-7,-3)?

Question

Sophia Alfred · Accepted Answer

21

Basis: #x = -4, Delta y = 4 - (-6) = 10 = B# basis: #x = -7, Delta y = 1 - (-3) = 4 = b# height = dist(Basis, basis) = #|-7 + 4| = 3 = h# Area = #1/2 (B + b) h = 1/2 cdot 14 cdot 3#

Savannah Aguilar · Answer

undefined To find the area of the trapezoid with vertices (-7,1), (-4,4), (-4,-6), and (-7,-3), you can use the formula for the area of a trapezoid:

$$ A = \frac{1}{2} \times \text{height} \times (\text{sum of parallel sides}) $$

First, calculate the lengths of the two parallel sides using the distance formula. Then, determine the height, which is the perpendicular distance between the parallel sides. Once you have these values, plug them into the formula to find the area.

Sophia Alfred · Answer

undefined To find the area of a trapezoid with vertices (-7,1), (-4,4), (-4,-6), and (-7,-3), you can use the formula for the area of a trapezoid:

Area = 0.5 * (sum of the lengths of the parallel sides) * (height)

The lengths of the parallel sides can be found by calculating the distance between the corresponding vertices. Then, the height of the trapezoid can be found by calculating the perpendicular distance between the two parallel sides.

Once you have the lengths of the parallel sides and the height, plug these values into the formula to find the area of the trapezoid.