How do you find the area of a trapezoid with base length 28, height 10, top side 8, and side lengths 12 and 15?

Answer 1

Area of the Trapezoid #= 180#

The Area of a Trapezoid is #A = {b_1 + b_2}/2 * h#
where #h# is the height, #b_1# is the base, and #b_2# is the "top side"

in other words, the Area of a Trapezoid is the "Average of the Bases times the Height"

in this case, #b_1 = 28# #b_2 = 8# and #h = 10#
which gives us #A = {28+8}/2 * 10# #A = 36/2 * 10# #A = 18 * 10 # #A = 180# #leftarrow# answer

*note: the "side lengths" are unnecessary information

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Answer 2

To find the area of a trapezoid, you can use the formula: [ Area = \frac{1}{2} \times (base_1 + base_2) \times height ]

In this case, base1 = 28, base2 = 8, and height = 10.

[ Area = \frac{1}{2} \times (28 + 8) \times 10 ] [ Area = \frac{1}{2} \times 36 \times 10 ] [ Area = 180 ]

So, the area of the trapezoid is 180 square units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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