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How do you find the area of a rhombus using its perimeter?

Answer 1

You need more information.

Area # = (p^2 sin theta)/16#

where #p# is the length of the perimeter and #theta# is one of the internal angles of the rhombus.

If the perimeter is of length #p# then the area is anywhere in the range #0# to #(p/4)^2 = p^2/16#
If the perimeter is of length #p# then the length of one side is #p/4#.

If we place one side of the rhombus horizontally, then the area is equal to the product of the base and height, The base is of length #p/4# and the height is #p/4 sin theta#, where #theta# is an internal angle of the rhombus.

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Answer 2

Allison Allen

To find the area of a rhombus using its perimeter, you can use the formula:

[ \text{Area} = \frac{p^2}{16} \times \sqrt{4a^2 - p^2} ]

Where:

( p ) is the perimeter of the rhombus,
( a ) is the length of one side of the rhombus.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.