How do you find the area of a circle if the circumference of a circle is 28.26cm?

Answer 1

#"area "~~63.55" cm"^2#

#"the area (A) of a circle is given by"#
#•color(white)(x)A=pir^2larrcolor(blue)"r is the radius"#
#"to calculate A we require to find r"#
#"the circumference (C) of a circle is given by"#
#•color(white)(x)C=2pir#
#"here "C=28.26 " so equating"#
#2pir=28.26#
#"divide both sides by "2pi#
#(cancel(2pi) r)/cancel(2pi)=28.26/(2pi)#
#r=28.26/(2pi)larr" round on final step"#
#"substitute this value into formula for A"#
#A=pixx(28.26/(2pi))^2~~63.55" to 2 dec. places"#
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Answer 2

To find the area of a circle when given the circumference, you use the formula:

Area = (Circumference)^2 / (4 * π)

Substitute the given circumference:

Area = (28.26)^2 / (4 * π)

Calculate the area using the value of π:

Area ≈ (28.26)^2 / (4 * 3.14159) ≈ 63.585 / 12.56636 ≈ 5.05 square centimeters.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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