How do you find the area between #y=x^3# and #y=6-x#?
There is no region bounded by just those two curves. So there is no area. (Or no finite area, if you prefer.)
Here is the graph:
graph{(y-x^3)(y-6+x)=0 [-15.22, 16.82, -4.36, 11.66]}
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To find the area between the curves (y = x^3) and (y = 6 - x), follow these steps:
- Find the points of intersection of the curves by setting them equal to each other: (x^3 = 6 - x).
- Solve for (x) to find the x-coordinates of the points of intersection.
- Integrate the difference of the upper curve (6 - x) and the lower curve (x^3) over the interval where they intersect.
- Take the absolute value of the resulting integral to ensure a positive area.
This process will give you the area between the curves (y = x^3) and (y = 6 - x).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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