# How do you find the area between #y=-3/8x(x-8), y=10-1/2x, x=2, x=8#?

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this is a sketch for your functions you can use this website to sketch them[www.desmos.com]

the area between the two curve equal

then complete the steps normally

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So the area enclosed by all four graphs is the area of the trapezium less the area under the curve.

45 - 27 = 18

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To find the area between the curves ( y = -\frac{3}{8}x(x-8) ), ( y = 10 - \frac{1}{2}x ), ( x = 2 ), and ( x = 8 ), you first need to find the points of intersection between the curves. Then, you integrate the absolute difference between the two functions over the interval of intersection, which is from the smallest x-coordinate of the intersection points to the largest x-coordinate. This gives you the area between the curves.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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