How do you find the antiderivative of #sin(x)cos(x)#?
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To find the antiderivative of sin(x)cos(x), you can use integration by parts. Let u = sin(x) and dv = cos(x) dx. Then, du = cos(x) dx and v = sin(x). Apply the integration by parts formula:
∫sin(x)cos(x) dx = sin(x)sin(x) - ∫sin(x)sin(x) dx
This simplifies to:
∫sin(x)cos(x) dx = -cos^2(x) + C
where C is the constant of integration.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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