How do you find the antiderivative of #int sin^2xcos^2x dx#?
The answer is
So,
So,
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To find the antiderivative of ( \int \sin^2(x) \cos^2(x) , dx ), use the trigonometric identity ( \sin^2(x) = \frac{1}{2}(1 - \cos(2x)) ) and ( \cos^2(x) = \frac{1}{2}(1 + \cos(2x)) ). Then integrate term by term. The antiderivative is:
[ \frac{1}{4}x - \frac{1}{8}\sin(2x) + C ]
where ( C ) is the constant of integration.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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