How do you find the antiderivative of #cos(3x)#?
we know
By signing up, you agree to our Terms of Service and Privacy Policy
The antiderivative of cos(3x) is found by applying the reverse of the chain rule. It's given by:
∫ cos(3x) dx = (1/3) sin(3x) + C
where C is the constant of integration.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you integrate #sin(3x) dx#?
- How do you find the area of the region under the curve #y=1/sqrt(2x-1)# from x=1/2, to x=1?
- How do you use Part 1 of the fundamental theorem of calculus to find the derivative of the function #y= int (1+v^2)^10 dv# from sinx to cosx? Please help have been looking at problem for a hour can't figure out how to work it?
- How do you find the definite integral of #int (3x-x^2)dx# from #[1,3]#?
- What is the antiderivative of #5/t^2#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7