# How do you find the angle between the planes 2x+5y-z=6 and 3x-2y+6z=10?

The angle is

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To find the angle between the planes (2x + 5y - z = 6) and (3x - 2y + 6z = 10), you can use the formula:

[ \cos \theta = \frac{{\text{{normal vector of plane 1}} \cdot \text{{normal vector of plane 2}}}}{{\lVert \text{{normal vector of plane 1}} \rVert \cdot \lVert \text{{normal vector of plane 2}} \rVert}} ]

- Find the normal vectors of the planes.
- Calculate the dot product of the normal vectors.
- Use the formula to find the angle ( \theta ).

After finding ( \theta ), you can use ( \cos^{-1} ) to find the angle in radians or degrees.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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