# How do you find the amplitude and period for #s = 1/2 cos (pit - 8)#?

By signing up, you agree to our Terms of Service and Privacy Policy

To find the amplitude and period of the function ( s = \frac{1}{2} \cos ( \pi t - 8 ) ), we first identify the coefficient of the cosine function as the amplitude, and the coefficient of ( t ) inside the parentheses of the cosine function as the frequency. The period of the function is then determined by dividing ( 2\pi ) by the frequency.

For the given function ( s = \frac{1}{2} \cos ( \pi t - 8 ) ), the amplitude is ( \frac{1}{2} ). The coefficient of ( t ) inside the parentheses of the cosine function is ( \pi ). Therefore, the frequency is ( \pi ), and the period ( T ) is given by:

[ T = \frac{2\pi}{\pi} = 2 ]

So, the amplitude of the function is ( \frac{1}{2} ), and the period is ( 2 ) units.

By signing up, you agree to our Terms of Service and Privacy Policy

- What are the important information needed to graph #y=tan(2x)#?
- Solve the equation #sech^(-1)x+lnx=3/2#, if #x>0#?
- How do you convert #-16.5^circ# from degree to radians?
- How do you find the critical points to graph #y=3sin(1/3x+ pi/2)-2#?
- The height (h) of the water in metres at a certain point at the wave pool over a period of seconds is modelled by the equation #h(s)=sin^2s+1/2sins+3/2#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7