# How do you find the 6-th partial sum of the infinite series #sum_(n=1)^oo1/n# ?

The 6th partial sum of the infinite series ( \sum_{n=1}^{\infty} \frac{1}{n} ) can be found by simply adding the first 6 terms of the series:

[ S_6 = \frac{1}{1} + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} ]

[ S_6 = 1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} ]

[ S_6 = 1 + 0.5 + 0.3333 + 0.25 + 0.2 + 0.1667 ]

[ S_6 = 2.55 ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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