# How do you find second derivative of #g(x)=sec(3x+1)#?

By signing up, you agree to our Terms of Service and Privacy Policy

To find the second derivative of ( g(x) = \sec(3x+1) ), follow these steps:

- Find the first derivative of ( g(x) ) using the chain rule.
- Then, find the second derivative by differentiating the result obtained in step 1.

First derivative of ( g(x) ):

[ g'(x) = \sec(3x+1) \tan(3x+1) \cdot 3 ]

Second derivative of ( g(x) ):

[ g''(x) = \frac{d}{dx} \left( \sec(3x+1) \tan(3x+1) \cdot 3 \right) ]

[ g''(x) = 3 \cdot \sec(3x+1) \tan(3x+1) \cdot \sec^2(3x+1) \cdot 3 ]

[ g''(x) = 9 \sec(3x+1) \tan(3x+1) \sec^2(3x+1) ]

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7