How do you find local maximum value of f using the first and second derivative tests: #f(x)= 5x  3#?
I think you haven't any max or min here.
Graphically: graph{5x3 [9.42, 10.58, 3.76, 13.76]}
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To find the local maximum value of ( f(x) = 5x  3 ) using the first and second derivative tests:

Find the first derivative of ( f(x) ) with respect to ( x ). ( f'(x) = 5 )

Find the critical points by setting ( f'(x) ) equal to zero. ( 5 = 0 ) has no solutions, so there are no critical points.

Since there are no critical points, there are no local maximum values for ( f(x) ) within its domain.
Therefore, there is no local maximum value for ( f(x) = 5x  3 ) using the first and second derivative tests.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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