# How do you find #lim (3x)/(4x-10)# as #x->-oo#?

Ignore the -10 since it's irrelevant when you get to high numbers such as infinity so treat the limit as:

Cancel out the x's:

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To find the limit of (3x)/(4x-10) as x approaches negative infinity, we can divide both the numerator and denominator by x. This gives us (3)/(4-(10/x)). As x approaches negative infinity, 10/x approaches 0. Therefore, the limit simplifies to 3/4.

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