# How do you find #int 1/sqrt(-x^2-4x)#?

By signing up, you agree to our Terms of Service and Privacy Policy

The answer is

The denominator is

Therefore, the integral is

Therefore,

The integral is

By signing up, you agree to our Terms of Service and Privacy Policy

To find the integral of ( \frac{1}{\sqrt{-x^2 - 4x}} ), we can start by completing the square in the denominator to simplify the expression. Then, we can use a trigonometric substitution. Let ( u = -x - 2 ). This substitution will help simplify the integral. After performing the substitution, you'll end up with an integral involving trigonometric functions. Finally, you can use trigonometric identities and integration techniques to solve the integral.

By signing up, you agree to our Terms of Service and Privacy Policy

- How do you integrate #int x/sqrt(3x^2-6x+10) dx# using trigonometric substitution?
- How do you integrate #int x^2lnx# by integration by parts method?
- How do you integrate #f(x)=(x^2-2)/((x+4)(x-2)(x-2))# using partial fractions?
- How do you integrate #sec(x)/(4-3tan(x)) dx#?
- How do I find the antiderivative of #f(x)=secxtanx(1+secx)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7