# How do you find #h(x+2)# given #h(x)=4x-2#?

To find ( h(x+2) ) given ( h(x) = 4x - 2 ), substitute ( x+2 ) for ( x ) in the expression for ( h(x) ):

[ h(x+2) = 4(x+2) - 2 ]

[ h(x+2) = 4x + 8 - 2 ]

[ h(x+2) = 4x + 6 ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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