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How do you find #(h+g)(10)# given #h(x)=3x+3# and #g(x)=-4x+1#?

Answer 1

Jameson Allen

To find (h+g)(10), substitute x = 10 into both h(x) and g(x), then add the results.

(h+g)(10) = h(10) + g(10) = (3(10) + 3) + (-4(10) + 1) = 30 + 3 - 40 + 1 = -6

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Answer 2

Eli Assouline

#=-6#

#h(x)=3x+3#

#g(x)=-4x+1#

#(h+g)(x)=3x+3-4x+1=-x+4#

#(h+g)(10)#

#=-10+4#

#=-6#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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