How do you find #h(4)# given #h(n)=n^3+6n#?
Isaiah AnthonyTo find ( h(4) ), substitute ( n = 4 ) into the function ( h(n) = n^3 + 6n ). So, ( h(4) = 4^3 + 6 \times 4 = 64 + 24 = 88 ). Therefore, ( h(4) = 88 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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