How do you find #g(h(24))# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?

Answer 1

First, find h(24) by substituting 24 into the expression for h(x): h(24) = 24^2 + 1 = 577. Then, find g(h(24)) by substituting h(24) into the expression for g(x): g(h(24)) = g(577) = 3 * 577 = 1731.

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Answer 2

Eli Assouline

#g(h(24))=1731#

Prior to evaluating g(h(24)), evaluate h(24)

#rArrh(color(red)(24))=(color(red)(24))^2+1#

#color(white)(rAerrh(24))=576+1#

#color(white)(rArrh(24)xx)=577#

Now enter this value in place of g(x).

#rArrg(h(24))=g(577)#

#=3xx577#

#=1731#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.