How do you find #g(f(h(-6)))# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?
To find ( g(f(h(-6))) ), first evaluate ( h(-6) ), then ( f(h(-6)) ), and finally ( g(f(h(-6))) ).
- ( h(-6) = (-6)^2 + 1 = 36 + 1 = 37 )
- ( f(h(-6)) = 2(37) - 1 = 74 - 1 = 73 )
- ( g(f(h(-6))) = 3(73) = 219 )
Therefore, ( g(f(h(-6))) = 219 ).
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219
Consequently
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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