How do you find five ordered pairs of #y^2 = x#?

Answer 1

#(0, 0), (1, -1), (1, 1), (4, 2), (4, -2)#

Given: #y^2 = x#
Rewrite the equation in #y = # form by square rooting both sides:
#y = +- sqrt(x)#
Since #x# is the independent variable, we can select values that we want to use to calculate #y#:
#ul(" "x" "|" "y" ")# #" "0" "|" "sqrt(0) = 0# #" "1" "|""+sqrt(1) = 1# #" "1" "|""-sqrt(1) = -1# #" "4" "|""+sqrt(4) = 2# #" "4" "|""-sqrt(4) = -2#
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Answer 2

To find five ordered pairs for the equation (y^2 = x), you can choose various values for (x) and solve for (y). Here are five ordered pairs:

  1. (x = 0): (y = \sqrt{0} = 0), so the ordered pair is ((0, 0)).
  2. (x = 1): (y = \sqrt{1} = 1), so the ordered pair is ((1, 1)).
  3. (x = 4): (y = \sqrt{4} = 2), so the ordered pair is ((4, 2)).
  4. (x = 9): (y = \sqrt{9} = 3), so the ordered pair is ((9, 3)).
  5. (x = 16): (y = \sqrt{16} = 4), so the ordered pair is ((16, 4)).

These are five ordered pairs that satisfy the equation (y^2 = x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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