# How do you find #f(x)# and #g(x)# when #h(x)= (x+1)^2 -9(x+1)# and #h(x)= (fog)(x)#?

##
The answers are:

#f(x)= x^2-9x# and

#g(x)= x+1#

but how?

The answers are:

but how?

See below.

Note that

NOTE

Taking into account

we have

This is a set of compatible values for two parameters.

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To find ( f(x) ) and ( g(x) ) when ( h(x) = (f \circ g)(x) ), we need to express ( h(x) ) in terms of ( f(x) ) and ( g(x) ) and then solve for each function.

Given that ( h(x) = (x+1)^2 - 9(x+1) ) and ( h(x) = (f \circ g)(x) ), we can equate the two expressions:

[ h(x) = f(g(x)) ]

Now, we can rewrite ( h(x) ) in terms of ( f(x) ) and ( g(x) ):

[ (x+1)^2 - 9(x+1) = f(g(x)) ]

From the given expression, we can see that ( g(x) = x + 1 ) and ( f(x) = x^2 - 9x ).

Therefore, ( f(x) = x^2 - 9x ) and ( g(x) = x + 1 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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