How do you find (f o g)(x) if #g(x) = (x^2 -16)^(1/2)#, #f(x) = (3 - x)^(1/2)#?

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x} ), you firstTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform theTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluateTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the compositionTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate (To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition ofTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( gTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions byTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substitTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x)To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substitutingTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) )To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) andTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (gTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and thenTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plugTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)\To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug theTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x))To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the resultTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) intoTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result intoTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into (To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (fTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x)To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)\To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

SoTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (fTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ gTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x)To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x)To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) =To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) =To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = fTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrtTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(gTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x))To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 -To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16}To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (fTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(gTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ gTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x))To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x)To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrtTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) =To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrtTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 -To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 -To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 -To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}}To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

ThusTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus,To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

SoTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, (To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So,To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (fTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((fTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ gTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ gTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x)To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) =To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x)To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) =To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrtTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrtTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrtTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{xTo find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{xTo find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 -To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2 -To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}}To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} \To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}}To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ).To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}}\To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ).To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}}).To find ( (f \circ g)(x) ), where ( g(x) = \sqrt{x^2 - 16} ) and ( f(x) = \sqrt{3 - x} ), you first evaluate ( g(x) ) and then plug the result into ( f(x) ).

So,

[ g(x) = \sqrt{x^2 - 16} ]

[ f(g(x)) = \sqrt{3 - (\sqrt{x^2 - 16})} ]

Thus, ( (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ).To find ((f \circ g)(x)), where (g(x) = \sqrt{x^2 - 16}) and (f(x) = \sqrt{3 - x}), you need to perform the composition of functions by substituting (g(x)) into (f(x)).

[ (f \circ g)(x) = f(g(x)) ]

[ (f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}} ]

So, ((f \circ g)(x) = \sqrt{3 - \sqrt{x^2 - 16}}).