How do you find #f(-8)# given #f(x)=x^2-3x#?
To find f(-8) given f(x) = x^2 - 3x, substitute -8 for x in the equation. f(-8) = (-8)^2 - 3(-8). Simplify to get f(-8) = 64 + 24 = 88. Therefore, f(-8) = 88.
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In order to evaluate f(-8), change f(x) to x = - 8.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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