How do you find #f(3/4)# given #f(x)=-1+1/4x#?

Answer 1

Substitute (x = \frac{3}{4}) into the function (f(x) = -1 + \frac{1}{4}x) to find (f\left(\frac{3}{4})). The result is (-\frac{5}{4}).

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Answer 2

Eva Abramson

When you insert 0.75 in the function, the answer will be -0.8125

Simply enter 0.75=3/4 into the function equation to solve it.

Currently, you possess -1+(3/16) = -13/16 = -0.8125.

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Answer 3

Eli Assouline

I would prefer to retain fractions as the expression is given in fractions.

Given #f(x)=-1+1/4x# To find #f(3/4)#, insert value of #x# in both sides of the equation. We obtain #f(3/4)=-1+1/4xx3/4# #=>f(3/4)=-1+3/16# Simplifying RHS we obtain #f(3/4)=(-16+3)/16# #f(3/4)=-13/16#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.