How do you find #f(-1)# given #f(n)=-3n^2-4n #?

Answer 1

To find ( f(-1) ) given ( f(n) = -3n^2 - 4n ), substitute ( n = -1 ) into the function: [ f(-1) = -3(-1)^2 - 4(-1) ] [ f(-1) = -3(1) + 4 ] [ f(-1) = -3 + 4 ] [ f(-1) = 1 ]

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Answer 2

Eli Assouline

Just put -1 in n's place.

f(n)= -3n^2-4n = -3(-1)^2 - 4(-1) = -3(1) +4 = -3+4 = 1

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Answer 3

Eva Adamson

f( -1) = 1

Given f(n) then f(-1) means assign the value -1 to n. That is substitute n = -1 into the function.

#f(n)=-3n^2-4n#

#rArrf(-1)=-3(-1)^2-4(-1)=-(3xx1)-(4xx-1)#

#=-3-(-4)=-3+4=1#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.