# How do you find #(dy)/(dx)# given #y^2+3x=2#?

and using chain rule

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To find ( \frac{dy}{dx} ) given ( y^2 + 3x = 2 ), differentiate both sides of the equation with respect to ( x ) and solve for ( \frac{dy}{dx} ).

[ \frac{d}{dx}(y^2 + 3x) = \frac{d}{dx}(2) ] [ 2y \frac{dy}{dx} + 3 = 0 ] [ 2y \frac{dy}{dx} = -3 ] [ \frac{dy}{dx} = \frac{-3}{2y} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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