# How do you find #(dy)/(dx)# given #siny=x^2#?

so that:

By signing up, you agree to our Terms of Service and Privacy Policy

To find (dy)/(dx) given siny = x^2, differentiate both sides of the equation implicitly with respect to x and solve for (dy)/(dx).

The derivative of siny with respect to x is cos(y) * (dy)/(dx), and the derivative of x^2 with respect to x is 2x.

So, we have:

cos(y) * (dy)/(dx) = 2x

Now, solve for (dy)/(dx):

(dy)/(dx) = 2x / cos(y)

Keep in mind that the expression (dy)/(dx) will be in terms of both x and y.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you use the power rule to differentiate #f(x)=1-x^2+3x^3sqrtx#?
- How do you differentiate #f(x)=tan(3x-x^2) # using the chain rule?
- How do you find the derivative of # f(x) = 3xsin(2x)^2#?
- How do you differentiate #f(x)=(2x^2-4x+4)e^x# using the product rule?
- How do you differentiate #g(x)= 3tan4x *sin2x*cos2x# using the product rule?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7