# How do you find #(dy)/(dx)# given #-2y^2+3=x^3#?

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To find (dy)/(dx) given the equation -2y^2 + 3 = x^3, we differentiate both sides of the equation with respect to x using implicit differentiation.

First, we differentiate -2y^2 + 3 with respect to y to find (dy)/(dx):

d/dx(-2y^2 + 3) = d/dx(x^3) -4y(dy/dx) = 3x^2

Next, solve for (dy)/(dx):

(dy/dx) = (3x^2) / (-4y)

Therefore, (dy)/(dx) = (3x^2) / (-4y).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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